18d^2-54d+28=0

Solution for 18d^2-54d+28=0 equation:

18d^2-54d+28=0

a = 18; b = -54; c = +28;
Δ = b2-4ac
Δ = -542-4·18·28
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-30}{2*18}=\frac{24}{36}
=2/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+30}{2*18}=\frac{84}{36}
=2+1/3
$